3x^2-18x+81=201

Solution for 3x^2-18x+81=201 equation:

3x^2-18x+81=201

We move all terms to the left:

3x^2-18x+81-(201)=0

We add all the numbers together, and all the variables

3x^2-18x-120=0

a = 3; b = -18; c = -120;
Δ = b2-4ac
Δ = -182-4·3·(-120)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-42}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+42}{2*3}=\frac{60}{6}
=10
$